Steply

Factorise fully 3x² − 12.

Step by step, with the reason for every step · GCSE Maths Higher Paper 1 · GCSE Maths

Step by step

The question

Question: factor completely 3x² − 12.

Completely means: until no part can be factored any more.

3x2 − 12

1 Common factor first

3 goes into 12: 3 × 4 = 12.

So 3 goes into both.

So the common factor is 3.

3 × 4 = 12

We divide every term by it.

What is left goes in the bracket.

3x2 ÷ 3 = x2
−12 ÷ 3 = −4

So it is 3(x² − 4).

= 3(x2 − 4)

2 Count the terms

The bracket has 2 terms.

With 2 terms we look for two squares: one square take away another.

x² − 4 is one square take away another square.

x times x is x², so x² is x squared.

2 times 2 is 4.

The rule: one bracket with plus, one with minus.

a² − b² = (a + b)(a − b)
x2 = (x)², 4
= 2²

So we get 3(x + 2)(x − 2).

= 3(x + 2)(x − 2)

3 Look at each bracket

Brackets like x + 2 have just x and a number.

They can't be factored.

x + 2, x − 2: just x and a number

No bracket can be factored any more.

So we are done.

Careful!

Don't forget the common factor 3 in the answer.

Careful: not (x² − 4) ✗

4 Check

Let's check: we multiply it back out.

Each part of one bracket times each part of the other.

Check: (x + 2)(x − 2) = x2 − 2x + 2x − 4
= x2 − 4

Then the common factor times every part.

3(x2 − 4) = 3x2 − 12

We get 3x² − 12 again.

So it is right!

Let's look back.

First: common factor.

Then: count the terms.

Then: look at each bracket.

Last: check.

Answer
= 3(x + 2)(x − 2)

Your turn

Try this one yourself, then check your answer:

Factor completely 4x2 − 16
Show the answer
4(x + 2)(x − 2)

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