Steply

Solve 3x² − 10x − 8 = 0.

Step by step, with the reason for every step · GCSE Maths Higher Paper 1 · GCSE Maths

Step by step

The question

Question: solve 3x² − 10x − 8 = 0.

3x2 − 10x − 8 = 0

There is an x².

1 Find two numbers

There is a number in front of x², but it can still factor.

The rule: we split the middle into two parts.

Their numbers must multiply to first × last.

Here the first number is 3 and the last is −8.

3 × −8 = −24.

So we need two numbers that multiply to −24.

They must also add to the middle number, −10.

3 × (−8) = −24
? × ? = −24
? + ? = −10

They multiply to a minus number, so one number is plus and one is minus.

They add to a minus number, so the bigger one is minus.

When we add a plus and a minus, the bigger one wins.

× is − → one +, one −; bigger one −

We list the pairs that make 24, smallest first.

For each pair, we check two things: they multiply to 24, and the bigger take away the smaller is 10.

One is minus, so adding them is a take away.

multiply to 24 bigger − smaller = 10

1 × 24 = 24.

24 − 1 = 23.

Not 10.

1 × 24 = 24 ✓ 24 − 1 = 23 ✗

2 × 12 = 24.

12 − 2 = 10.

Both work!

2 × 12 = 24 ✓ 12 − 2 = 10 ✓

So the two numbers are 2 and 12.

With the signs: 2 and −12.

2 and 12

2 Split the middle

We write −10x as 2x − 12x.

It is the same amount.

3x2 + 2x − 12x − 8 = 0

3 Group in pairs

We put the first two together, and the last two together.

(3x2 + 2x) + (−12x − 8) = 0

3x² and 2x both have x in them.

So from the first pair we take out x.

−12x and −8 both have −4 in them.

So from the second pair we take out −4.

We take out the minus too, so the bracket matches the first one.

Both leave the same bracket.

(3x2 + 2x) = x(3x + 2)
(−12x − 8) = −4(3x + 2)

Now both parts have 3x + 2 in them.

x(3x + 2) − 4(3x + 2) = 0

4 Same bracket out

3x + 2 is in both parts, so we take it out once.

What is left, x − 4, goes in the other bracket.

ab + cb = b(a + c)

So we get (3x + 2)(x − 4).

(3x + 2)(x − 4) = 0

5 One bracket is 0

Two numbers multiply to 0.

That only happens if one of them is 0.

So one bracket must be 0.

A × B = 0 → A = 0 or B = 0

We make each bracket 0.

Two small equations.

3x + 2 = 0 or x − 4 = 0

In 3x + 2 = 0, we take away 2 on both sides.

In x − 4 = 0, we add 4 on both sides.

3x + 2 − 2 = 0 − 2 or x − 4 + 4 = 0 + 4

Now we have 3x = −2 or x = 4.

3x = −2 or x = 4

To remove times 3, we divide both sides by 3.

So x = −2/3 or x = 4.

x = −23 or x = 4

6 Check

Let's check: put x = −2/3 into the left side.

x = −23: 3(−23)2 − 10(−23) − 8
= 43 + 203 − 8 = 0

We get 0, the same as the right side.

It works!

Now put x = 4 into the left side.

x = 4: 3(4)2 − 10(4) − 8 = 48 − 40 − 8 = 0

We get 0 again, the same as the right side.

So both answers are right!

Let's look back.

First: find two numbers.

Then: split the middle.

Then: group in pairs.

Then: same bracket out.

Then: one bracket is 0.

Last: check.

Answer
x = −23 or x = 4

Your turn

Try this one yourself, then check your answer:

Solve 4x2 − 13x − 12 = 0
Show the answer
x = −34 or x = 4

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