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Find all zeros of f(x) = x^3 - x^2 - 10x - 8

Step by step, with the reason for every step · Finding all zeros · Algebra 2

Step by step

The question

Question: find all the zeros of f(x) = x³ − x² − 10x − 8.

f(x) = x3 − x2 − 10x − 8

A zero of f is an x that makes f(x) equal 0.

A power 3 has up to three zeros.

a zero: an x where f(x) = 0

1 List the candidates

The rational root theorem: a whole or fraction zero is a factor of the last number, over a factor of the first number.

whole or fraction zero = factor of the last numberfactor of the first number

The last number is −8.

Its factors are 1, 2, 4, 8, each with plus and minus.

factors of 8 : ±1, ±2, ±4, ±8

Careful!

Don't forget the negative ones.

−1, −2 and the others can be zeros too.

Careful: every candidate has + and −

The first number is 1.

So the candidates are just these.

candidates : ±1, ±2, ±4, ±8

2 Test the candidates

We put each candidate into f.

When we get 0, we found a zero.

Then x minus that number is a factor, like in the factor theorem lesson.

f(c) = 0 → (x − c) is a factor

Start with 1: put it in place of every x.

f(1) = 13 − 12 − 10(1) − 8

We get −18, not 0.

So 1 is not a zero.

= 1 − 1 − 10 − 8 = −18 ✗

Next −1: put it in place of every x.

f(−1) = (−1)3 − (−1)2 − 10(−1) − 8

We get 0.

So x = −1 is a zero!

= −1 − 1 + 10 − 8 = 0 zero!

3 Divide by x + 1

x = −1 is a zero, so (x + 1) is a factor.

We divide it out, with synthetic division.

x + 1 is 0 when x is −1.

So we use −1.

Then we write just the numbers in front: 1, −1, −10, −8.

The first number comes straight down: 1.

1 times −1 is −1.

Write it under the next number.

Add: −1 + (−1) is −2.

−2 times −1 is 2.

Write it under the next number.

Add: −10 + 2 is −8.

−8 times −1 is 8.

Write it under the next number.

Add: −8 + 8 is 0.

The last number is the remainder: 0.

The other numbers are the answer's numbers: 1, −2, −8.

The answer starts one power lower than x³.

So f(x) = (x + 1)(x² − 2x − 8).

The other zeros come from x² − 2x − 8 = 0.

f(x) = (x + 1)(x² − 2x − 8)

4 Solve the quadratic

Now x² − 2x − 8 = 0, with the quadratic lesson.

x2 − 2x − 8 = 0

5 Factor

We need two numbers.

They multiply to −8, and they add to −2.

? × ? = −8
? + ? = −2

They multiply to a minus number, so one number is plus and one is minus.

They add to a minus number, so the bigger one is minus.

× is − → one +, one −; bigger one −

We list the pairs that make 8, smallest first.

We take the smaller from the bigger.

We need 2.

2 and 4 give 2.

Yes!

With the signs: 2 and −4.

1 × 8: 8 − 1 = 7
2 × 4: 4 − 2 = 2 ✓

So it is (x + 2)(x − 4) = 0.

(x + 2)(x − 4) = 0

6 One bracket is 0

Two numbers multiply to 0.

That only happens if one of them is 0.

So one bracket must be 0.

A × B = 0 → A = 0 or B = 0

We make each bracket 0.

Two small equations.

x + 2 = 0 or x − 4 = 0

In x + 2 = 0, we take away 2 on both sides.

In x − 4 = 0, we add 4 on both sides.

x + 2 − 2 = 0 − 2 or x − 4 + 4 = 0 + 4

So x = −2 or x = 4.

x = −2 or x = 4

7 Write all the zeros

So the zeros are −1, −2 and 4.

−1 from the test, the others from the quadratic.

zeros : x = −1 or x = −2 or x = 4

8 Check

Let's check: put −2 into f.

We get 0.

x = −2: f = (−2)3 − (−2)2 − 10(−2) − 8
= −8 − 4 + 20 − 8 = 0

And put 4 into f.

We get 0 too.

x = 4: f = 43 − 42 − 10(4) − 8
= 64 − 16 − 40 − 8 = 0

Let's look back.

First: list the candidates.

Then: test the candidates.

Then: divide by x + 1.

Then: solve the quadratic.

Then: factor.

Then: one bracket is 0.

Then: write all the zeros.

Last: check.

Answer
zeros : x = −1 or x = −2 or x = 4

Your turn

Try this one yourself, then check:

find all zeros of f(x) = x3 + 2x2 − 5x − 6
Show the answer
x = −1 or x = 2 or x = −3

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