Step by step
The question
Question: find the limit as x → 16 of (√x − 4)/(x − 16).
1 Put the number in
Put 16 in place of x.
The top is 0, and the bottom is 0.
The square root of 16 is 4.
4 minus 4 is 0.
0/0 has no value.
It tells us to work more.
2 Multiply by the conjugate
The conjugate of √x − 4 is √x + 4: the same two terms, with the sign swapped.
Multiply the top and the bottom by the conjugate.
Something over itself is 1.
So the value does not change.
Careful!
Both the top and the bottom!
One alone would change the value.
3 Multiply out
Remember: a minus b, times a plus b, is a squared minus b squared.
The middle terms cancel.
On top: (√x − 4) times (√x + 4).
That is the root squared, minus 4 squared.
The bottom we leave as it is.
A square root squared is just what is inside.
So it is x − 16.
Now (x − 16) is on the top and on the bottom.
4 Cancel
x gets close to 16, but it is never 16.
So x − 16 is not 0.
Something over itself is 1.
So we cross out (x − 16) on the top and the bottom.
Write what is left: 1 over (√x + 4).
5 Put the number in again
Now the 0 is gone.
Put 16 in again.
The square root of 16 is 4.
So the limit is 1/8.
6 Check
Let's check with numbers close to 16.
A calculator gives 0.125 at x = 15.99.
And 0.125 at x = 16.01.
Both are close to 1/8, which is 0.125.
Right!
Let's look back.
First: put the number in.
Then: multiply by the conjugate.
Then: multiply out.
Then: cancel.
Then: put the number in again.
Last: check.