Steply

Find the sum 16 - 8 + 4 - 2 + ...

Step by step, with the reason for every step · Series · Algebra 2

Step by step

The question

Question: find the sum 16 − 8 + 4 − 2 + and so on.

The dots at the end mean: it goes on forever.

16 − 8 + 4 − 2 + ...

1 Find the ratio

2 Look at the sums

1/2 is less than 1.

Each new term is smaller, and the sign flips.

So the sums jump up and down, but less each time: they settle down near one number.

|r| = 12 < 1

Let's add the terms one at a time, and write each running sum: 16, 8, 12, and so on.

3 Use the sum rule

In the sum rule, r to the power n gets closer and closer to 0.

So it drops out, and the sum is the first term over 1 minus r.

S = a11 − r

Careful!

r is negative.

1 minus a minus is 1 plus: 3/2, not 1/2.

Careful: not 1 − (−12) = 12 ✗

Put in a₁ = 16 and r = −1/2.

S = 161 − (−12)

1 + 1/2 is 3/2.

So we divide by 3/2.

S = 16 ÷ 32

Dividing by 3/2 is times its flip, 2/3.

S = 16 × 23

So the sum is 32/3.

S = 323

4 Check

Let's check: we keep adding terms.

The running sums are 10.5, 10.75, 10.625.

sums: 10, 11, 10.5, 10.75, 10.625, ...

They get closer and closer to 32/3.

It works!

closer and closer to 10.67

Let's look back.

First: find the ratio.

Then: look at the sums.

Then: use the sum rule.

Last: check.

Answer
S = 323

Your turn

Try this one yourself, then check:

find the sum 12 − 6 + 3 − 32 + ...
Show the answer
8

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