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Find the sum 64 + 16 + 4 + 1 + ...

Step by step, with the reason for every step · Series · Algebra 2

Step by step

The question

Question: find the sum 64 + 16 + 4 + 1 + and so on.

The dots at the end mean: it goes on forever.

64 + 16 + 4 + 1 + ...

1 Find the ratio

2 Look at the sums

1/4 is less than 1.

Each new term is smaller.

So the sums settle down near one number.

|r| = 14 < 1

Let's add the terms one at a time, and write each running sum: 64, 80, 84, and so on.

3 Use the sum rule

In the sum rule, r to the power n gets closer and closer to 0.

So it drops out, and the sum is the first term over 1 minus r.

S = a11 − r

Careful!

The terms go on forever, but the sum does not: each term is smaller than the one before.

Careful: forever, but the sum is not endless

Put in a₁ = 64 and r = 1/4.

S = 641 − 14

1 − 1/4 is 3/4.

So we divide by 3/4.

S = 64 ÷ 34

Dividing by 3/4 is times its flip, 4/3.

S = 64 × 43

So the sum is 256/3.

S = 2563

4 Check

Let's check: we keep adding terms.

The running sums are 85.313, 85.328, 85.332.

sums: 85, 85.25, 85.313, 85.328, 85.332, ...

They get closer and closer to 256/3.

It works!

closer and closer to 85.33

Let's look back.

First: find the ratio.

Then: look at the sums.

Then: use the sum rule.

Last: check.

Answer
S = 2563

Your turn

Try this one yourself, then check:

find the sum 4 + 2 + 1 + 12 + ...
Show the answer
8

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