Steply

Graph x = t - 2, y = t^2 - 4 for -1 ≤ t ≤ 3

Step by step, with the reason for every step · Parametric equations · Precalculus

Step by step

The question

Question: graph and remove t from x = t − 2, y = t² − 4, for −1 ≤ t ≤ 3.

x = t − 2 and y = t2 − 4

1 Make a table

Each t gives a point.

Start with t = −1.

x is (−1) − 2: −3.

t = −1: x = (−1) − 2 = −3

y is (−1)² − 4: −3.

Minus times minus is plus.

y = (−1)² − 4 = −3

Put the t's in a table: t from −1 to 3.

Work out x for each t,

−3
−2
−1
0
1

and y for each t.

−3
−4
−3
0
5

2 Plot the points

Draw the grid.

Put each (x, y) on the grid.

3 Join in order of t

Join the points in order: t = −1, then 0, and on.

The arrows show the way t grows.

4 Remove t

To get t alone, start with x = t − 2.

To remove − 2, we add 2.

We do it on both sides, so they stay equal.

x + 2 = t − 2 + 2

So t = x + 2.

t = x + 2

Put t into y = t² − 4, with its bracket: y = (x + 2)² − 4.

y = (x + 2)2 − 4

Careful!

The whole of x + 2 is squared, not only the last number.

So it keeps its bracket.

Careful: not y = x + 2² − 4 ✗

5 Check

Let's check with a point from the table: t = 3 gave (1, 5).

Put x = 1 into the answer.

We get y = 5, the same as the table.

Right!

x = 1: y = (1 + 2)² − 4 = 5

Let's look back.

First: make a table.

Then: plot the points.

Then: join in order of t.

Then: remove t.

Last: check.

Answer
Careful: not y = x + 2² − 4 ✗

Your turn

Try this one yourself, then check:

x = t − 3, y = t² − 3, for −1 ≤ t ≤ 3
Show the answer
y = (x + 3)2 − 3

More from Parametric equations

The whole lesson: Parametric equations →