Steply

Graph x^2 = 16y

Step by step, with the reason for every step · Parabola · Precalculus

Step by step

The question

Question: find the focus and the directrix of x² = 16y.

x2 = 16y

1 Find p

Compare with the parabola rule: x² = 4py.

rule: x² = 4py

So 4p is the number in front of y: 4p = 16.

4p = 16

Careful!

16 is 4p, not p.

We still divide by 4.

Careful: not p = 16 ✗

To remove times 4, we divide by 4.

We do it on both sides, so they stay equal.

4p4 = 164

4 divided by 4 is 1.

So just p is left.

16 divided by 4 is 4.

So p = 4.

p = 4

2 Focus and directrix

There are no brackets: just x² and y.

So the vertex is (0, 0).

vertex = (0, 0)

p is positive.

So the parabola opens up.

p > 0: opens up

The focus is 4 above the vertex, inside the curve: (0, 4).

focus = (0, 4)

The directrix is the flat line 4 on the other side of the vertex: y = −4.

directrix: y = −4

So the focus is (0, 4) and the directrix is y = −4.

focus (0, 4) and y = −4

3 Draw it

Draw the grid.

The vertex (0, 0),

the focus (0, 4),

and the directrix y = −4, dashed.

The parabola opens up, around the focus.

4 Check

Let's check with a point on the parabola, level with the focus: (8, 4).

Is it on the parabola?

Put it in: 64 and 64.

Yes!

8² = 16 × 4 → 64 = 64

Its distance to the focus: 8.

Its distance to the directrix: 8 too.

The same distance.

That is what makes a parabola.

Right!

to the focus 8, to the directrix 8

Let's look back.

First: find p.

Then: focus and directrix.

Then: draw it.

Last: check.

Answer
focus (0, 4) and y = −4

Your turn

Try this one yourself, then check:

Find the focus and the directrix of x2 = 4y
Show the answer
focus (0, 1) and y = −1

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