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Integrate ∫ (e^x + 3/x) dx

Step by step, with the reason for every step · Integrals with e and ln · Calculus 2

Step by step

The question

Question: find the integral of eˣ + 3 over x.

∫ (ex + 3x) dx =

1 The rules

First, e to the x.

Its derivative is eˣ itself: its slope equals its height.

So its integral is eˣ + C too.

∫ ex dx = ex + C

Now 1 over x.

The power rule cannot do it: x to the −1 would become x to the 0, over 0.

Instead: the derivative of ln x is 1 over x.

So the integral of 1/x is ln|x| + C.

∫ 1x dx = ln|x| + C

The bars mean the size of x.

ln only takes positive numbers, and x may be negative.

|x|: ln needs a number > 0

Careful!

The power rule fails for 1/x: the new power would be 0, and we cannot divide by 0.

Use ln.

Careful: not x00 ✗

2 Each term

e to the x stays e to the x.

∫ ex dx = ex

3 times 1 over the bottom gives 3 ln|x|.

∫ 3x dx = 3ln|x|

Put the terms together, and add C: the slope cannot tell us a number added on the end.

So the answer is eˣ + 3 ln|x| + C.

= ex + 3ln|x| + C

3 Check

Let's check: take the derivative of our answer.

ln of the bottom gives its slope over the bottom.

derivative: ex + 3 × 1x

The numbers cancel, and we get eˣ + 3/x: the question again.

Right!

= ex + 3x

Let's look back.

First: the rules.

Then: each term.

Last: check.

Answer
= ex + 3ln|x| + C

Your turn

Try this one yourself, then check:

∫ (5ex + 1x) dx
Show the answer
5ex + ln|x| + C

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