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Integrate ∫ -6/x dx

Step by step, with the reason for every step · Integrals with e and ln · Calculus 2

Step by step

The question

Question: find the integral of −6 over x.

∫ −6x dx =

1 The rules

Now 1 over x.

The power rule cannot do it: x to the −1 would become x to the 0, over 0.

Instead: the derivative of ln x is 1 over x.

So the integral of 1/x is ln|x| + C.

∫ 1x dx = ln|x| + C

The bars mean the size of x.

ln only takes positive numbers, and x may be negative.

|x|: ln needs a number > 0

Careful!

The power rule fails for 1/x: the new power would be 0, and we cannot divide by 0.

Use ln.

Careful: not x00 ✗

2 Integrate

6 times 1 over the bottom gives 6 ln|x|.

Add C: the slope cannot tell us a number added on the end.

So the answer is −6 ln|x| + C.

∫ −6x dx = −6ln|x| + C

3 Check

Let's check: take the derivative of our answer.

ln of the bottom gives its slope over the bottom.

derivative: −6 × 1x

The numbers cancel, and we get −6/x: the question again.

Right!

= −6x

Let's look back.

First: the rules.

Then: integrate.

Last: check.

Answer
∫ −6x dx = −6ln|x| + C

Your turn

Try this one yourself, then check:

∫ −2x dx
Show the answer
−2ln|x| + C

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