Step by step
The question
Question: find the integral from 0 to 1 of 2x times (x² + 1)³.
1 Choose u
The inside: x² + 1.
Call it u.
Its derivative is 2x, and 2x is outside.
A good sign: u′ is there, or nearly.
2 Find du
The power rule: du/dx = 2x.
Multiply both sides by dx: du = 2x dx.
A small change in u is 2x times a small change in x.
3 Change the limits
The limits 0 and 1 are x values.
u needs its own: x = 0 gives u = 1.
And x = 1 gives u = 2.
4 Write it with u
x² + 1 becomes u, and 2x dx becomes du.
The limits are the u values.
Careful!
Not the old limits!
0 and 1 are x values, but now we work with u.
5 Integrate
Integrate: add 1 to the power, divide by the new power.
3 plus 1 is 4.
6 Top minus bottom
Put in 2, then take away the same with 1.
Work out the powers.
So the integral is 15/4.
7 Check
Let's check without changing the limits: put x back in the antiderivative, and use the x limits 0 and 1.
A calculator gives 4 minus 0.25: 3.75.
The same number.
Right!
Let's look back.
First: choose u.
Then: find du.
Then: change the limits.
Then: write it with u.
Then: integrate.
Then: top minus bottom.
Last: check.