Steply

Is (1, 2, 3), (0, 1, 1) a basis for R^3

Step by step, with the reason for every step · Basis and coordinates · Linear Algebra

Step by step

The question

Question: are (1, 2, 3) and (0, 1, 1) a basis for R³?

v1 = [1; 2; 3], v2 = [0; 1; 1]

A basis for R³ is a set of vectors that are independent, and that make every vector of R³ as a linear combination.

basis for R³: independent, and every vector
is a linear combination of them

1 Count the vectors

There are 2 vectors, but every basis for R³ has exactly 3.

2 vectors cannot reach every vector of R³.

2 vectors, but R³ needs 3

So they are not a basis.

= not a basis

2 Check

Let's check with one vector: (1, 0, 0).

We try to make it from them.

The vectors as columns, then this one after the bar.

= [1, 0, 1; 2, 1, 0; 3, 1, 0]

Row reduced, as before.

Row 3 says 0 = −1: false.

→ [1, 0, 1; 0, 1, −2; 0, 0, −1]

So (1, 0, 0) cannot be made from them.

They do not reach every vector: the answer is right!

Let's look back.

First: count the vectors.

Last: check.

Answer
= not a basis

Your turn

Try this one yourself, then check:

Basis for R³? [1; 4; 1], [0; 1; 3]
Show the answer
not a basis

More from Basis and coordinates

The whole lesson: Basis and coordinates →