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Is (1, 2), (3, 4), (5, 6) a basis for R^2

Step by step, with the reason for every step · Basis and coordinates · Linear Algebra

Step by step

The question

Question: are (1, 2), (3, 4) and (5, 6) a basis for R²?

v1 = [1; 2], v2 = [3; 4], v3 = [5; 6]

A basis for R² is a set of vectors that are independent, and that make every vector of R² as a linear combination.

basis for R²: independent, and every vector
is a linear combination of them

1 Count the vectors

There are 3 vectors, but every basis for R² has exactly 2.

3 vectors in R² cannot be independent.

3 vectors, but R² needs 2

So they are not a basis.

= not a basis

2 Check

Let's check: they must be dependent.

Row reducing, as in the independence lesson, gives v₁ − 2v₂ + v₃ = 0.

= [1; 2] − 2 × [3; 4] + [5; 6]
= [1; 2] − [2 × 3; 2 × 4] + [5; 6]
= [1; 2] − [6; 8] + [5; 6]
= [1 − 6 + 5; 2 − 8 + 6]
= [0; 0]

We get the zero vector, and not all the numbers are 0.

So they are dependent: the answer is right!

Let's look back.

First: count the vectors.

Last: check.

Answer
= not a basis

Your turn

Try this one yourself, then check:

Basis for R²? [2; 4], [3; 2], [4; 5]
Show the answer
not a basis

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