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Magnitude and direction of <-4, -4>

Step by step, with the reason for every step · Magnitude and direction, unit vector · Precalculus

Step by step

The question

Question: find the magnitude and the direction of v = ⟨−4, −4⟩.

v = ⟨−4, −4⟩

1 Draw the arrow

Draw the grid.

The arrow starts at the origin.

It goes left 4 and down 4.

Across 4 and down 4 make a right triangle.

2 Find the length

The length ‖v‖: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

‖v‖ = √(−4)2 + (−4)2

Write the squares: 16 + 16.

‖v‖ = √16 + 16

16 plus 16 is 32.

‖v‖ = √32

But 32 has a square number in it: 16.

32 is 16 times 2.

‖v‖ = √16 × 2

A root of a times splits into two roots.

‖v‖ = √16 × √2

√16 is 4.

4 × 4 = 16

So ‖v‖ = 4√2.

That is the exact answer, made simple.

‖v‖ = 4√2

3 Find the angle in the triangle

In the right triangle, tan is opposite over adjacent: up over across.

We use the sizes, with no signs.

We call this small angle α.

tan α = 44

4 divided by 4 is 1.

4 ÷ 4 = 1

The tan⁻¹ button turns it back into the angle.

α = tan−1(1)

The calculator gives exactly 45.

So α = 45°.

α = 45°

Here is α on the grid.

4 Which way it points

The direction θ always turns from the right side of the x-axis, going up and round.

The arrow points left and down.

θ is a half turn, 180°, and then α more.

left and down: θ = 180° + α

So θ = 180° + 45°.

θ = 180° + 45°

Careful!

45° alone points right and up.

Our arrow points left and down.

Always look at the picture.

Careful: not θ = 45° ✗

180 plus 45 is 225.

So θ = 225°.

θ = 225°

So the magnitude is 4√2 and the direction is 225°.

‖v‖ = 4√2 and θ = 225°

5 Check

Let's check: tan of 225° on the calculator is 1.

Up over across, with the signs: −4 over −4 is 1.

The same!

tan 225° = 1, −4−4 = 1

Let's look back.

First: draw the arrow.

Then: find the length.

Then: find the angle in the triangle.

Then: which way it points.

Last: check.

Answer
‖v‖ = 4√2 and θ = 225°

Your turn

Try this one yourself, then check:

Find the magnitude and the direction of v⟨−5, −5⟩
Show the answer
‖v‖ = 5√2 and θ = 225°

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