Steply

Magnitude of <1, 2, 2>

Step by step, with the reason for every step · Vectors in space · Calculus 3

Step by step

The question

Question: find the length of v = ⟨1, 2, 2⟩.

v = ⟨1, 2, 2⟩

1 Draw it

Draw the three axes.

The arrow starts at the origin.

Go 1 along x, 2 along y, 2 along z.

The arrow goes from the origin to the end of that path.

2 Find the length

The length ‖v‖ is Pythagoras with three parts.

Square each part, add, then take the square root.

‖v‖ = √12 + 22 + 22

1 squared is 1.

2 squared is 4.

2 squared is 4.

‖v‖ = √1 + 4 + 4

Add: 1 plus 4 plus 4 is 9.

‖v‖ = √9

3 times 3 is 9.

3 × 3 = 9

So ‖v‖ = 3.

‖v‖ = 3

Careful!

We don't add the parts.

The arrow is the long side of a right triangle, so we square, add, and take the root.

Careful: not ‖v‖ = 1 + 2 + 2 ✗

3 Check

Let's check it as Pythagoras twice.

Across the floor the square is 5.

Then up z: 5 plus 4 is 9.

The same!

floor: 1 + 4 = 5, then 5 + 4 = 9

Let's look back.

First: draw it.

Then: find the length.

Last: check.

Answer
Careful: not ‖v‖ = 1 + 2 + 2 ✗

Your turn

Try this one yourself, then check:

Find the length of v = ⟨2, 2, 1⟩
Show the answer
‖v‖ = 3

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