Steply

Magnitude of <2, 3, 6>

Step by step, with the reason for every step · Vectors in space · Calculus 3

Step by step

The question

Question: find the length of v = ⟨2, 3, 6⟩.

v = ⟨2, 3, 6⟩

1 Draw it

Draw the three axes.

The arrow starts at the origin.

Go 2 along x, 3 along y, 6 along z.

The arrow goes from the origin to the end of that path.

2 Find the length

The length ‖v‖ is Pythagoras with three parts.

Square each part, add, then take the square root.

‖v‖ = √22 + 32 + 62

2 squared is 4.

3 squared is 9.

6 squared is 36.

‖v‖ = √4 + 9 + 36

Add: 4 plus 9 plus 36 is 49.

‖v‖ = √49

7 times 7 is 49.

7 × 7 = 49

So ‖v‖ = 7.

‖v‖ = 7

Careful!

We don't add the parts.

The arrow is the long side of a right triangle, so we square, add, and take the root.

Careful: not ‖v‖ = 2 + 3 + 6 ✗

3 Check

Let's check it as Pythagoras twice.

Across the floor the square is 13.

Then up z: 13 plus 36 is 49.

The same!

floor: 4 + 9 = 13, then 13 + 36 = 49

Let's look back.

First: draw it.

Then: find the length.

Last: check.

Answer
Careful: not ‖v‖ = 2 + 3 + 6 ✗

Your turn

Try this one yourself, then check:

Find the length of v = ⟨1, 8, 4⟩
Show the answer
‖v‖ = 9

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