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Vectors in space

Calculus 3 ยท 23 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Draw it
  2. Work part by part
  3. Find the length
  4. Check

The steps for Vector from (1, 2, 3) to (4, 6, 3). Every solution names its steps, so you always know what comes next.

Worked examples

Vector from (1, 2, 3) to (4, 6, 3) Easy

The question

Question: find the vector from (1, 2, 3) to (4, 6, 3), and its length.

(1, 2, 3) to (4, 6, 3)

1 Draw it

Draw the three axes: x toward us, y right, z up.

The arrow starts at (1, 2, 3)

and ends at (4, 6, 3).

Draw the arrow from the start to the end.

We call it v.

2 Work part by part

Each part is end minus start: x minus x, y minus y, z minus z.

v = โŸจ4 โˆ’ 1, 6 โˆ’ 2, 3 โˆ’ 3โŸฉ
end โˆ’ start

Careful!

Not start minus end.

That gives an arrow pointing the other way.

Careful: not โŸจโˆ’3, โˆ’4, 0โŸฉ โœ—

4 minus 1 is 3.

6 minus 2 is 4.

3 minus 3 is 0.

So v = โŸจ3, 4, 0โŸฉ.

v = โŸจ3, 4, 0โŸฉ

3 Find the length

The length โ€–vโ€– is Pythagoras with three parts.

Square each part, add, then take the square root.

โ€–vโ€– = โˆš32 + 42 + 02

3 squared is 9.

4 squared is 16.

0 squared is 0.

โ€–vโ€– = โˆš9 + 16 + 0

Add: 9 plus 16 plus 0 is 25.

โ€–vโ€– = โˆš25

5 times 5 is 25.

5 ร— 5 = 25

So โ€–vโ€– = 5.

โ€–vโ€– = 5

4 Check

Let's check: start at (1, 2, 3) and add the parts.

We land on (4, 6, 3), the end!

(1 + 3, 2 + 4, 3 + 0) = (4, 6, 3)

And the length squared is 25, the sum of the squares.

Right!

5ยฒ = 25

Let's look back.

First: draw it.

Then: work part by part.

Then: find the length.

Last: check.

Answer
v = โŸจ3, 4, 0โŸฉ

โ–ถ Watch it solved

Vector from (2, -1, 4) to (4, 1, 5) Medium

The question

Question: find the vector from (2, โˆ’1, 4) to (4, 1, 5), and its length.

(2, โˆ’1, 4) to (4, 1, 5)

1 Draw it

Draw the three axes: x toward us, y right, z up.

The arrow starts at (2, โˆ’1, 4)

and ends at (4, 1, 5).

Draw the arrow from the start to the end.

We call it v.

2 Work part by part

Each part is end minus start: x minus x, y minus y, z minus z.

v = โŸจ4 โˆ’ 2, 1 โˆ’ (โˆ’1), 5 โˆ’ 4โŸฉ
end โˆ’ start

Careful!

Not start minus end.

That gives an arrow pointing the other way.

Careful: not โŸจโˆ’2, โˆ’2, โˆ’1โŸฉ โœ—

4 minus 2 is 2.

1 minus (โˆ’1) is 2.

5 minus 4 is 1.

So v = โŸจ2, 2, 1โŸฉ.

v = โŸจ2, 2, 1โŸฉ

3 Find the length

The length โ€–vโ€– is Pythagoras with three parts.

Square each part, add, then take the square root.

โ€–vโ€– = โˆš22 + 22 + 12

2 squared is 4.

2 squared is 4.

1 squared is 1.

โ€–vโ€– = โˆš4 + 4 + 1

Add: 4 plus 4 plus 1 is 9.

โ€–vโ€– = โˆš9

3 times 3 is 9.

3 ร— 3 = 9

So โ€–vโ€– = 3.

โ€–vโ€– = 3

4 Check

Let's check: start at (2, โˆ’1, 4) and add the parts.

We land on (4, 1, 5), the end!

(2 + 2, โˆ’1 + 2, 4 + 1) = (4, 1, 5)

And the length squared is 9, the sum of the squares.

Right!

3ยฒ = 9

Let's look back.

First: draw it.

Then: work part by part.

Then: find the length.

Last: check.

Answer
v = โŸจ2, 2, 1โŸฉ

โ–ถ Watch it solved

Magnitude of <1, 2, 3> Harder

The question

Question: find the length of v = โŸจ1, 2, 3โŸฉ.

v = โŸจ1, 2, 3โŸฉ

1 Draw it

Draw the three axes.

The arrow starts at the origin.

Go 1 along x, 2 along y, 3 along z.

The arrow goes from the origin to the end of that path.

2 Find the length

The length โ€–vโ€– is Pythagoras with three parts.

Square each part, add, then take the square root.

โ€–vโ€– = โˆš12 + 22 + 32

1 squared is 1.

2 squared is 4.

3 squared is 9.

โ€–vโ€– = โˆš1 + 4 + 9

Add: 1 plus 4 plus 9 is 14.

โ€–vโ€– = โˆš14

14 is not a square number.

So โˆš14 is the exact length.

โ€–vโ€– = โˆš14

With a calculator, that is about 3.7, to the nearest tenth.

โ€–vโ€– โ‰ˆ 3.7

Careful!

We don't add the parts.

The arrow is the long side of a right triangle, so we square, add, and take the root.

Careful: not โ€–vโ€– = 1 + 2 + 3 โœ—

3 Check

Let's check it as Pythagoras twice.

Across the floor the square is 5.

Then up z: 5 plus 9 is 14.

The same!

floor: 1 + 4 = 5, then 5 + 9 = 14

Let's look back.

First: draw it.

Then: find the length.

Last: check.

Answer
Careful: not โ€–vโ€– = 1 + 2 + 3 โœ—

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. vector from (1, 2, 3) to (4, 6, 3)
    Answer
    v = โŸจ3, 4, 0โŸฉ
  2. vector from (0, 1, 2) to (2, 3, 3)
    Answer
    v = โŸจ2, 2, 1โŸฉ
  3. magnitude of <2, 3, 6>
    Answer
    Careful: not โ€–vโ€– = 2 + 3 + 6 โœ—
  4. magnitude of <1, 2, 2>
    Answer
    Careful: not โ€–vโ€– = 1 + 2 + 2 โœ—
  5. magnitude of <4, 4, 7>
    Answer
    Careful: not โ€–vโ€– = 4 + 4 + 7 โœ—
  6. u = <1, -2, 2>, find 3u
    Answer
    Careful: not โŸจ3, โˆ’2, 2โŸฉ โœ—
  7. u = <2, 0, -1>, find -2u
    Answer
    Careful: not โŸจโˆ’4, 0, โˆ’1โŸฉ โœ—
  8. u = <1, 2, 3>, v = <4, 0, -1>, find u + v
    Answer
    u + v = โŸจ5, 2, 2โŸฉ

Medium

  1. vector from (2, -1, 4) to (4, 1, 5)
    Answer
    v = โŸจ2, 2, 1โŸฉ
  2. vector from (3, 2, 1) to (5, 5, 7)
    Answer
    v = โŸจ2, 3, 6โŸฉ
  3. unit vector of <2, -1, 2>
    Answer
    Careful: not โŸจ2, โˆ’1, 2โŸฉ โˆ’ 3 โœ—
  4. unit vector of <3, 4, 12>
    Answer
    Careful: not โŸจ3, 4, 12โŸฉ โˆ’ 13 โœ—
  5. unit vector of <6, 2, 3>
    Answer
    Careful: not โŸจ6, 2, 3โŸฉ โˆ’ 7 โœ—
  6. u = <1, 2, 3>, v = <4, 0, -1>, find 2u + v
    Answer
    2u + v = โŸจ6, 4, 5โŸฉ
  7. u = <3, -1, 2>, v = <1, 4, -2>, find u - v
    Answer
    u โˆ’ v = โŸจ2, โˆ’5, 4โŸฉ
  8. u = <2, 1, 0>, v = <-1, 3, 2>, find 3u - 2v
    Answer
    3u โˆ’ 2v = โŸจ8, โˆ’3, โˆ’4โŸฉ
  9. magnitude of <-2, 6, 9>
    Answer
    Careful: not โ€–vโ€– = โˆ’2 + 6 + 9 โœ—
  10. vector from (1, 0, -2) to (3, 6, 1)
    Answer
    v = โŸจ2, 6, 3โŸฉ

Harder

  1. magnitude of <1, 2, 3>
    Answer
    Careful: not โ€–vโ€– = 1 + 2 + 3 โœ—
  2. magnitude of <2, 2, 4>
    Answer
    Careful: not โ€–vโ€– = 2 + 2 + 4 โœ—
  3. vector from (1, 1, 1) to (2, 3, 4)
    Answer
    v = โŸจ1, 2, 3โŸฉ
  4. unit vector of <-4, 4, 2>
    Answer
    Careful: not โŸจโˆ’4, 4, 2โŸฉ โˆ’ 6 โœ—
  5. u = <1, -2, 4>, v = <2, 1, -3>, find 2u - 3v
    Answer
    2u โˆ’ 3v = โŸจโˆ’4, โˆ’7, 17โŸฉ