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Negate ∃y (y^2 + 1 = 0)

Step by step, with the reason for every step · Negating with quantifiers · Discrete Math

Step by step

The question

Question: write the opposite of ∃y (y² + 1 = 0).

∃y (y2 + 1 = 0)

The backwards E means: there is some.

∀ = for every
∃ = there is some

1 Put not in front

The opposite of a statement: we put not in front of all of it.

Now we move the not inside, one piece at a time.

= ¬∃y (y2 + 1 = 0)

2 Move the not inside

There is no y means: for every y, it fails.

So ¬∃ becomes ∀¬.

≡ ∀y ¬(y2 + 1 = 0)
¬∃ = ∀¬

Careful!

There is none means every one fails, not just one.

Careful: not ∃y ¬(y² + 1 = 0) ✗

3 Turn the inside around

The opposite of y² + 1 = 0 is y² + 1 ≠ 0.

≡ ∀y (y2 + 1 ≠ 0)
¬(a = b) is a ≠ b

4 Say it in words

In words: for every y, with y² + 1 ≠ 0.

= for every y: y² + 1 ≠ 0

5 Check

Let's check with y = 3.

The first inside: 10 = 0, that is false.

y = 3: y2 + 1 = 0 gives 10 = 0: F

The new inside: 10 ≠ 0, that is true.

One true, one false: opposite, as they must be.

Right!

y = 3: y2 + 1 ≠ 0 gives 10 ≠ 0: T

Let's look back.

First: put not in front.

Then: move the not inside.

Then: turn the inside around.

Then: say it in words.

Last: check.

Answer
¬(a = b) is a ≠ b

Your turn

Try this one yourself, then check:

Write the opposite of ∃y (y2 + 1 > 0)
Show the answer
∀y (y² + 1 ≤ 0)

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