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Prove the sum of two multiples of 7 is a multiple of 7

Step by step, with the reason for every step · Direct proof · Discrete Math

Step by step

The question

Question: prove that the sum of two multiples of 7 is a multiple of 7.

1 Write it with letters

x is a multiple of 7, so x = 7a, where a is a whole number.

x = 7a

That is what a multiple of 7 means.

a multiple of 7 = 7 × a whole number

y is a multiple of 7, so y = 7b, where b is a whole number.

A new letter, b: y can be a different number from x.

y = 7b

Careful!

The same letter would make x and y the same number.

Two numbers need two letters.

Careful: not x = 7a, y = 7a ✗

2 Put them in

Now put them in: x + y becomes (7a) + (7b).

x + y = (7a) + (7b)

3 Work it out

Open the brackets: 7a + 7b.

= 7a + 7b

4 Show the form

Every term has a 7 in it.

We take out 7: 7(a + b).

= 7(a + b)

a + b is a whole number, because whole numbers added and multiplied stay whole.

a + b is a whole number

7 times a whole number: so x + y is a multiple of 7.

So x + y is a multiple of 7. ∎

The square at the end means: the proof is done.

5 Check

An example: x = 7 and y = 14.

It gives 21.

x = 7, y = 14: 7 + 14 = 21

21 is 7 times 3: a multiple of 7, as the proof says.

Right!

21 = 7 × 3

Let's look back.

First: write it with letters.

Then: put them in.

Then: work it out.

Then: show the form.

Last: check.

Answer
a + b is a whole number

Your turn

Try this one yourself, then check:

Show the answer
xy = 4 × 4ab

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