Right angle at A, AD ⊥ BC, BD = 2, BC = 7, find AB

Step by step

The question

Question: triangle A B C has a right angle at A, and A D is at 90° to B C, with BD = 2, BC = 7: find AB.

1 Find the similar triangles

The height A D cuts the big triangle into two small ones.

All three triangles have a right angle, and they share their other angles.

So they are similar: the same shape.

2 Write the rule

Triangles D B A and A B C: B D over A B equals A B over B C.

Cross-multiplied, that gives the rule: AB squared is BD times BC.

Careful!

It is BD times BC, not plus.

3 Put the numbers in

Put the numbers in.

We call AB x.

2 times 7 is 14.

4 Take the square root

x is the square root of 14.

A length is positive: 3.7, to the nearest tenth.

5 Check

Let's check with Pythagoras in the small triangle A B D: A D squared plus B D squared is 14, about the same as A B squared.

So it fits!

Let's look back.

First: find the similar triangles.

Then: write the rule.

Then: put the numbers in.

Then: take the square root.

Last: check.