Step by step
The question
Question: work out (3 + 2i) + (1 − 5i).
(3 + 2i) + (1 − 5i)
No real number times itself is negative.
So we use a new number: i, the square root of minus 1.
So i squared is minus 1.
i = √(−1)
i² = −1
1 Open the brackets
A bracket with a plus or nothing in front can just be removed.
= 3 + 2i + 1 − 5i
2 Group like parts
Like parts go together: the plain numbers are the real parts.
The parts with i go together too.
Real parts: 3 + 1 = 4.
i parts: 2i − 5i = −3i.
3 + 1 = 4
2i − 5i = −3i
So the answer is 4 − 3i.
= 4 − 3i
3 Check
Let's check: take away 1 − 5i.
We should get the first number again: 3 + 2i.
Check: (4 − 3i) − (1 − 5i) = 3 + 2i
Let's look back.
First: open the brackets.
Then: group like parts.
Last: check.
Answer
= 4 − 3i