Steply

Solve 2 cos^2 x - cos x = 0

Step by step, with the reason for every step · Trig equations · Trigonometry

Step by step

The question

Question: solve 2 cos² x − cos x = 0.

Find every angle from 0° up to 360°.

2 cos2 x − cos x = 0

We want the angles from 0° to 360°: one full turn.

0° ≤ x < 360°

Careful!

Do not divide by cos x!

That throws away cos x = 0, and its answers.

We take cos x out instead.

Careful: not ÷ cos x ✗

1 Take out the common factor

Both parts have cos x in them.

We take it out, like a common factor.

cos x(2 cos x − 1) = 0

Check the first part: cos x times 2 cos x is 2 cos squared x.

cos x × 2 cos x = 2 cos² x

2 Set each factor to 0

Two things times each other make 0.

That only happens when one of them is 0.

So cos x = 0, or...

cos x = 0

...

2 cos x − 1 = 0.

2 cos x − 1 = 0

We want cos x by itself.

Two things are stuck to cos x: times 2 and − 1.

The − 1 is on the outside, so it comes off first.

Then the times 2.

3 Remove the − 1

To remove − 1, we add 1.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

2 cos x − 1 + 1 = 0 + 1

− 1 and + 1 make zero.

Cross them out.

0 + 1 = 1.

0 + 1 = 1

Now we have 2 cos x = 1.

2 cos x = 1

4 Remove the 2

2 cos x means 2 times cos x.

We want just cos x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2 cos x2 = 12

2 divided by 2 is 1.

So just cos x is left.

So cos x = 1/2!

cos x = 12

5 Find the reference angle

From the unit circle: cos 60° = 1/2.

So the reference angle is 60°.

cos 60° = 12

6 Find every angle

Cos is the across value.

The points with the across value we want are on an up-and-down line, one line for each value.

Cos is 0 straight up and straight down.

x = 90° or 270°.

cos x = 0: x = 90° or 270°

Cos is positive right of the y-axis: quadrants I and IV.

60° and 360° − 60°: x = 60° or 300°.

cos x = 12: x = 60° or 300°

On the circle: 4 points, so 4 angles.

So x = 60°, 90°, 270°, 300°.

x = 60°, 90°, 270°, 300°

7 Check

Let's check every answer in the equation.

Each one must give 0.

x = 60°: 2 cos² 60° − cos 60° = 2 × (12)² − 12 = 0
x = 90°: 2 cos² 90° − cos 90° = 2 × (0)² − 0 = 0
x = 270°: 2 cos² 270° − cos 270° = 2 × (0)² − 0 = 0
x = 300°: 2 cos² 300° − cos 300° = 2 × (12)² − 12 = 0

Every answer works.

So x = 60°, 90°, 270°, 300°.

Let's look back.

First: take out the common factor.

Then: set each factor to 0.

Then: remove the − 1.

Then: remove the 2.

Then: find the reference angle.

Then: find every angle.

Last: check.

Answer
x = 60°, 90°, 270°, 300°

Your turn

Try this one yourself, then check:

2 sin2 x − sin x = 0
Show the answer
x = 0°, 30°, 150°, 180°

More from Trig equations

The whole lesson: Trig equations →