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Solve 3|x + 2| - 4 <= 5

Step by step, with the reason for every step · Absolute value inequalities · Algebra 1

Step by step

The question

Question: solve 3|x + 2| − 4 ≤ 5.

3|x + 2| − 4 ≤ 5

1 Get the bars alone

We want the bars by themselves.

The − 4 is in the way, so we add 4 on both sides.

3|x + 2| − 4 + 4 ≤ 5 + 4

− 4 and + 4 make zero.

Cross them out.

5 plus 4 is 9.

3|x + 2| ≤ 9

To remove times 3, we divide both sides by 3.

3 is a positive number, so the sign stays the same.

3|x + 2|3 ≤ 93

3 divided by 3 is 1.

So just the bars is left.

9 divided by 3 is 3.

|x + 2| ≤ 3

2 Draw the distance

3 Write it without bars

So x + 2 is between −3 and 3: −3 ≤ x + 2 ≤ 3.

Now x is in the middle.

−3 ≤ x + 2 ≤ 3

4 Remove the + 2

We want x by itself.

The + 2 is in the way.

To remove + 2, we take away 2.

We do it to all three parts.

Why all three?

The signs compare the three parts.

If we change only one part, the answer can change.

−3 − 2 ≤ x + 2 − 2 ≤ 3 − 2

+ 2 and − 2 make zero.

Cross them out.

−3 minus 2 is −5.

3 minus 2 is 1.

−3 − 2 = −5
3 − 2 = 1

Now we have −5 ≤ x ≤ 1.

So x is between −5 and 1: −5 ≤ x ≤ 1.

−5 ≤ x ≤ 1

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A square bracket means the end is in, like the filled circle.

interval: [−5, 1]

6 Check

Let's test one number from the answer: −1.

We put it in the question.

The inside is 1, and the bars make it 1.

x = −1: 3|−1 + 2| − 4 = 3|1| − 4 = 3(1) − 4
= −1

−1 is less than or equal to 5.

True!

So the answer works.

−1 ≤ 5

Let's look back.

First: get the bars alone.

Then: draw the distance.

Then: write it without bars.

Then: remove the + 2.

Then: show it on a number line.

Last: check.

Answer
−5 ≤ x ≤ 1

Your turn

Try this one yourself, then check:

Solve 6|x + 2| − 8 ≤ 10
Show the answer
−5 ≤ x ≤ 1

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