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Solve x + 2 > 1 and x - 3 < 4

Step by step, with the reason for every step · Compound inequalities with and / or · Algebra 1

Step by step

The question

Question: solve x + 2 > 1 and x − 3 < 4.

"And" means both parts must be true.

x + 2 > 1 and x − 3 < 4
and: both true

1 Solve the first part

First part: x + 2 > 1.

x + 2 > 1

We want x by itself.

The + 2 is in the way.

To remove + 2, we take away 2.

We do it on both sides, so the sign stays true.

x + 2 − 2 > 1 − 2

+ 2 and − 2 make zero.

Cross them out.

1 − 2 = −1.

1 − 2 = −1

So x is greater than −1.

x > −1

2 Solve the second part

Second part: x − 3 < 4.

x − 3 < 4

We want x by itself.

The − 3 is in the way.

To remove − 3, we add 3.

We do it on both sides, so the sign stays true.

x − 3 + 3 < 4 + 3

− 3 and + 3 make zero.

Cross them out.

4 + 3 = 7.

4 + 3 = 7

So x is less than 7.

x < 7

3 Show each part on a number line

4 Find the numbers in both

"And": we keep only the numbers that are shaded on both lines.

So −1 < x < 7.

x is between −1 and 7.

= −1 < x < 7

Careful!

A number that is shaded on only one line is not an answer.

It must be on both.

Careful: and: only where BOTH lines are shaded

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

interval: (−1, 7)

5 Check

Let's test one number from the answer: 3.

"And": it must work in both parts.

First part.

First: 3 + 2 = 5

5 is greater than 1.

True!

5 > 1

Now the second part.

Second: 3 − 3 = 0

0 is less than 4.

True!

So the answer works.

0 < 4

Let's look back.

First: solve the first part.

Then: solve the second part.

Then: show each part on a number line.

Then: find the numbers in both.

Last: check.

Answer
Careful: and: only where BOTH lines are shaded

Your turn

Try this one yourself, then check:

Solve x + 2 > −1 and x − 3 < 1
Show the answer
−3 < x < 4

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