Step by step
The question
Question: a square pyramid has base 10 and height 6: find the angle between a slant edge and the base.
1 Find the right triangle
The line is the slant edge A V, from a corner of the base up to the top, V.
Its shadow on the base goes from A to M, the middle of the base, right under the top.
M V is the height, straight up.
So A M V is a right triangle, right angle at M.
2 Half the diagonal
First the whole diagonal of the square base, A C: 10 squared plus 10 squared is 200.
A M is half of A C.
Half a length gives a quarter of its square: 200 divided by 4 is 50.
So A M is the square root of 50.
That is about 7.1.
Careful!
M is the middle of the base.
From a corner to M is half of the diagonal, not half of a side.
3 The angle
θ is at A.
The side across from it goes up: 6.
The side next to it is the shadow, AM.
Tan is opposite over adjacent.
To get the angle back, we use tan to the minus 1 on a calculator: about 40.3°, to the nearest tenth.
4 Check
Let's check another way.
The whole line AV is the square root of 50 plus 36.
Sin θ is 6 over that.
Sin to the minus 1 gives 40.3° again.
So it is right!
Let's look back.
First: find the right triangle.
Then: half the diagonal.
Then: the angle.
Last: check.