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Square pyramid base 2 height 3, angle between a slant edge and the…

Step by step, with the reason for every step · Trigonometry in 3D · Geometry

Step by step

The question

Question: a square pyramid has base 2 and height 3: find the angle between a slant edge and the base.

1 Find the right triangle

The line is the slant edge A V, from a corner of the base up to the top, V.

Its shadow on the base goes from A to M, the middle of the base, right under the top.

M V is the height, straight up.

So A M V is a right triangle, right angle at M.

2 Half the diagonal

First the whole diagonal of the square base, A C: 2 squared plus 2 squared is 8.

AC2 = 2² + 2² = 8

A M is half of A C.

Half a length gives a quarter of its square: 8 divided by 4 is 2.

AM2 = 8 ÷ 4 = 2

So A M is the square root of 2.

That is about 1.4.

AM = √2 ≈ 1.4

Careful!

M is the middle of the base.

From a corner to M is half of the diagonal, not half of a side.

Careful: the shadow is half the diagonal, not half the side

3 The angle

θ is at A.

The side across from it goes up: 3.

The side next to it is the shadow, AM.

Tan is opposite over adjacent.

tan θ = 3√2
tan = opposite ÷ adjacent

To get the angle back, we use tan to the minus 1 on a calculator: about 64.8°, to the nearest tenth.

θ = tan⁻¹(3√2) ≈ 64.8°

4 Check

Let's check another way.

The whole line AV is the square root of 2 plus 9.

Sin θ is 3 over that.

Sin to the minus 1 gives 64.8° again.

So it is right!

AV = √(2 + 9) = √11, sin⁻¹(3 ÷ √11) ≈ 64.8°

Let's look back.

First: find the right triangle.

Then: half the diagonal.

Then: the angle.

Last: check.

Answer
θ = tan⁻¹(3√2) ≈ 64.8°

Your turn

Try this one yourself, then check:

Find the angle θ.
Show the answer
θ ≈ 67.0°

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