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The area of a circle grows at 20 cm²/s. How fast is the radius…

Step by step, with the reason for every step · Related rates · Calculus

Step by step

The question

Question: The area of a circle grows at 20 cm²/s.

How fast is the radius growing when the radius is 5 cm?

1 Draw and name

Draw it.

The radius r grows, so the area A grows too.

The area grows by 20 cm² per second: dA/dt = 20.

dAdt = 20 cm²/s

dr/dt means how fast r changes: the change each second.

drdt: how fast r changes, per second

We want dr/dt at the moment when r = 5.

drdt = ?

2 Write the equation

The area of a circle: A = π r squared.

A = πr2

Careful!

Do not put r = 5 in yet!

r changes with time.

Numbers go in only after the derivative.

Careful: not A = π(5)² first ✗

3 Take the derivative

Both A and r change with time.

The chain rule: r squared gives 2r times dr/dt.

π just waits.

dAdt = 2πr drdt

4 Put the numbers in

Put in dA/dt = 20 and r = 5.

20 = 2π(5) drdt

Multiply the numbers: 2 × 5 = 10.

20 = 10π drdt

5 Solve for the rate

To remove times 10π, divide both sides by 10π.

drdt = 2010π

Simplify: 2 over π.

= 2π

With π ≈ 3.14159, about 0.64 cm per second.

≈ 0.64 cm/s

6 Check

Let's check: a tiny moment later, 0.001 seconds.

The area is 0.02 bigger.

Then r is about 5.000637.

A + 0.02: r ≈ 5.000637

r grew by 0.000637.

That is about 0.64 cm per second.

Right!

change ÷ 0.001 ≈ 0.64

Let's look back.

First: draw and name.

Then: write the equation.

Then: take the derivative.

Then: put the numbers in.

Then: solve for the rate.

Last: check.

Answer
≈ 0.64 cm/s

Your turn

Try this one yourself, then check:

Show the answer
The radius grows at about 0.32 cm/s.

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