Step by step
The question
Question: find the number c from the mean value theorem for f(x) = x³ on [0, 3].
The theorem: for some c between a and b, the slope at c equals the average slope from a to b.
There are four choices.
First we solve it, the normal way.
Then we pick.
1 Check the conditions
f is a polynomial.
Its graph has no breaks and no sharp corners.
So it is continuous on [0, 3], and smooth between.
The theorem can be used.
The ends: f of 0 is 0.
And f of 3 is 27.
2 The average slope
The average slope from 0 to 3: the change in f over the change in x.
It is 9.
Careful!
Divide by the width, 3 minus 0.
The average slope is 9, not 27.
3 Find c
The slope: use the power rule.
Now we have f′(x) = 3x².
At c the slope is the average slope: f′(c) = 9.
Divide by 3.
Take the square root.
A plus number and a minus number both square to it.
So c is plus or minus √3, about 1.73.
4 Keep the ones inside
c, about 1.73, is between 0 and 3.
Keep it.
c, about −1.73, is not between 0 and 3.
It does not count.
So c = √3, about 1.73.
5 Check
Let's check: put c into f′.
We get 9, the average slope.
Right!
6 Pick the choice
Our answer is c = √3 ≈ 1.73.
That is choice C.
7 Why not the others
A is 1.5.
Wrong: the middle of the interval: c must give f′(c) = 9.
B is 3.
Wrong: that is c²: take its square root.
D is 9.
Wrong: that is the slope of the chord.
Let's look back.
First: check the conditions.
Then: the average slope.
Then: find c.
Then: keep the ones inside.
Then: check.
Then: pick the choice.
Last: why not the others.