Steply

What is the limit of (x^2 + 2x - 3)/(x^2 - 1) as x approaches 1?

Step by step, with the reason for every step · AP Calculus AB Practice Exam 2 · AP Calculus AB

Step by step

The question

Question: find the limit as x → 1 of (x² + 2x − 3)/(x² − 1).

lim x → 1 x2 + 2x − 3x2 − 1

There are four choices.

First we solve it, the normal way.

Then we pick.

1 Put the number in

Put 1 in place of x.

The top is 0, and the bottom is 0.

12 + 2(1) − 312 − 1 = 1 + 2 − 31 − 1 = 00

0/0 has no value.

It does not tell us the limit.

It tells us to work more.

00: no value yet. Work more!

Careful!

0/0 is not 0, and it is not 1.

Some piece of the top and the bottom is 0 at 1.

We find it.

Careful: not 00 = 0 ✗

2 Factor

x − 1 is the piece that is 0 at x = 1.

The top and the bottom are both 0 there, so both have (x − 1) in them.

We factor them.

To factor x² + 2x − 3, the rule: we need two numbers that multiply to −3 and add to 2.

They are 3 and −1: they multiply to −3 and add to 2.

? × ? = −3
? + ? = 2
3 × (−1) = −3, 3 + (−1) = 2 ✓

1 is 1 times 1.

So x² − 1 is x² minus 1²: one square take away another square.

The rule: a² − b² = (a − b)(a + b).

So it is (x − 1)(x + 1).

1 = 1 × 1
= 1²
a² − b² = (a − b)(a + b)

Now we write the top and the bottom in factors.

lim x → 1 x2 + 2x − 3x2 − 1 = lim x → 1 (x − 1)(x + 3)(x − 1)(x + 1)

3 Cancel

x gets close to 1, but it is never 1.

So x − 1 is not 0.

x ≠ 1, so x − 1 ≠ 0

A number over itself is 1.

So we cross out (x − 1) on the top and the bottom.

Write what is left: (x + 3)/(x + 1).

= lim x → 1 (x + 3)(x + 1)

4 Put the number in again

Now x − 1 is gone, so the bottom is not 0.

Put 1 in again.

= 1 + 31 + 1
= 42

So the limit is 2.

= 2

5 Check

Let's check with numbers close to 1.

x = 0.99 gives about 2.005.

x = 0.99: f(x) ≈ 2.005

x = 1.01 gives about 1.995.

Both are close to 2.

Right!

x = 1.01: f(x) ≈ 1.995

6 Pick the choice

Our answer is limit = 2.

That is choice B.

B) 2

7 Why not the others

A is 0.

Wrong: put in 1 at once: 0/0 means simplify first.

That is the Careful mistake from before.

A) 0 ✗ put in 1 at once: 0 over 0 means simplify first

C is 1.

Wrong: cancelled the x²: the factors are (x + 3)(x − 1) and (x + 1)(x − 1).

C) 1 ✗ cancelled the x^2: the factors are (x + 3)(x − 1) and (x + 1)(x − 1)

D is 4.

Wrong: lost the + 1 of the bottom.

D) 4 ✗ lost the + 1 of the bottom

Let's look back.

First: put the number in.

Then: factor.

Then: cancel.

Then: put the number in again.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
= 2

Your turn

Try this one yourself, then check your answer:

lim x → 3 x2 − 4x + 3x2 − 5x + 6
Show the answer
limit = 2

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