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Write 2 + 4 + 8 + 16 + 32 using sigma notation

Step by step, with the reason for every step · Sigma notation · Algebra 2

Step by step

The question

Question: write 2 + 4 + 8 + 16 + 32 using sigma notation.

2 + 4 + 8 + 16 + 32

1 Find the rule

The rule from the sequences lesson, with i for the term number: the first term, times 2 to the power (i − 1).

r = 2: ai = 2 × 2i − 1

2 times 2 to the power (i − 1) is 2 to the power i: one more 2.

ai = 2 × 2i − 1 = 2i

2 Count the terms

i counts the terms: 1, 2, 3, 4, 5.

There are 5 terms.

So i starts at 1 and stops at 5.

i = 1, 2, 3, 4, 5

Careful!

The stop number on Σ is the last i, 5.

It is not the last term, 32.

Careful: not Σi = 1322i ✗

3 Write it with Σ

So we write: the sum for i = 1 to 5 of 2 to the power i.

= Σi = 152i

4 Check

Let's check: put i = 1, 2, up to 5 into 2 to the power i.

We get each term of the list.

i = 1 to 5: 2 + 4 + 8 + 16 + 32

That is the sum we started with.

It works!

Let's look back.

First: find the rule.

Then: count the terms.

Then: write it with Σ.

Last: check.

Answer
= Σi = 152i

Your turn

Try this one yourself, then check:

write 3 + 9 + 27 + 81 + 243 with Σ
Show the answer
Σi = 153i

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