Steply

Write down an expression for the nth term of 4, 9, 14, 19, ...

Step by step, with the reason for every step · GCSE Maths Foundation Paper 1 · GCSE Maths

Step by step

The question

Question: 4, 9, 14, 19, …: find the rule for term n.

A sequence is a list of numbers in order.

4, 9, 14, 19, ...

1 Find the difference

From 4 to 9, we add 5.

From 9 to 14, we add 5 again.

We add 5 every time.

A list like this is an arithmetic sequence.

The number we add is called the difference: d = 5.

d = 5

2 Find the rule

Term 1 is 4.

a1 = 4

a₁ is term 1, a₂ is term 2.

So aₙ is term number n.

an = term number n

Term 2: we add 5 one time.

a2 = 4 + 1 × 5

Term 3: we add it two times.

a3 = 4 + 2 × 5

We add 5 one time less than the term number.

times we add 5 = term number − 1

So for term n, we add 5, (n − 1) times.

an = 4 + (n − 1) × 5

This rule works for every arithmetic sequence: the first term, plus (n − 1) times the difference.

an = a1 + (n − 1) × d

3 Make the rule simpler

Open the bracket: each part inside is times 5.

n times 5 is 5n.

The − 1 inside, times 5, is −5.

an = 4 + 5n − 5

Plain numbers go together: 4 − 5 is −1.

4 − 5 = −1

So the rule is aₙ = 5n − 1.

an = 5n − 1

4 Check

Let's check the rule with a term we know.

Put n = 4.

a4 = 5 × 4 − 1 = 20 − 1 = 19

We get 19.

That is term 4 in the list.

So the rule is right!

Let's look back.

First: find the difference.

Then: find the rule.

Then: make the rule simpler.

Last: check.

Answer
an = 5n − 1

Your turn

Try this one yourself, then check your answer:

1, 5, 9, 13, ... find an
Show the answer
an = 4n − 3

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