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Write x^2 - 10x + 30 in vertex form

Step by step, with the reason for every step · Vertex form by completing the square · Algebra 2

Step by step

The question

Question: write y = x² − 10x + 30 in vertex form.

y = x2 − 10x + 30

Vertex form is a times (x minus h) squared, plus k.

The vertex, the turning point, is (h, k).

vertex form: a(x − h)2 + k

1 Complete the square

We add 25 to fill the corner.

And we take 25 away straight after, so nothing changes.

= x2 − 10x + 25 − 25 + 30

2 Write the square

The full square is x − 5 on each side.

So these three parts are (x − 5) squared.

x2 − 10x + 25 = (x − 5)2

We write the bracket squared.

The rest stays.

= (x − 5)2 − 25 + 30

3 Tidy up

−25 plus 30 is 5.

−25 + 30 = 5

So y = (x − 5)² + 5.

This is vertex form.

= (x − 5)2 + 5

4 Read the vertex

In vertex form we need x minus h.

x − 5 is x minus 5.

So h = 5, and k = 5.

x − 5 = x − 5

So the vertex is (5, 5).

vertex = (5, 5)

Careful!

x minus 5 means h is 5, not −5.

The sign in the bracket is the opposite of h.

Careful: not vertex (−5, 5) ✗

5 Check

Let's check: open the brackets again.

(x − 5) squared is x² − 10x + 25.

Check: (x − 5)2 + 5 = x2 − 10x + 25 + 5
= x2 − 10x + 30

We get x² − 10x + 30 again.

It works!

Let's look back.

First: complete the square.

Then: write the square.

Then: tidy up.

Then: read the vertex.

Last: check.

Answer
= (x − 5)2 + 5

Your turn

Try this one yourself, then check:

y = x2 − 8x + 7 in vertex form
Show the answer
y = (x − 4)2 − 9

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