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Write x^2 + 6x + 5 in vertex form

Step by step, with the reason for every step · Vertex form by completing the square · Algebra 2

Step by step

The question

Question: write y = x² + 6x + 5 in vertex form.

y = x2 + 6x + 5

Vertex form is a times (x minus h) squared, plus k.

The vertex, the turning point, is (h, k).

vertex form: a(x − h)2 + k

1 Complete the square

We add 9 to fill the corner.

And we take 9 away straight after, so nothing changes.

= x2 + 6x + 9 − 9 + 5

2 Write the square

The full square is x + 3 on each side.

So these three parts are (x + 3) squared.

x2 + 6x + 9 = (x + 3)2

We write the bracket squared.

The rest stays.

= (x + 3)2 − 9 + 5

3 Tidy up

−9 plus 5 is −4.

−9 + 5 = −4

So y = (x + 3)² − 4.

This is vertex form.

= (x + 3)2 − 4

4 Read the vertex

In vertex form we need x minus h.

x + 3 is x minus (−3).

So h = −3, and k = −4.

x + 3 = x − (−3)

So the vertex is (−3, −4).

vertex = (−3, −4)

Careful!

x plus 3 means h is −3, not 3.

The sign in the bracket is the opposite of h.

Careful: not vertex (3, −4) ✗

5 Check

Let's check: open the brackets again.

(x + 3) squared is x² + 6x + 9.

Check: (x + 3)2 − 4 = x2 + 6x + 9 − 4
= x2 + 6x + 5

We get x² + 6x + 5 again.

It works!

Let's look back.

First: complete the square.

Then: write the square.

Then: tidy up.

Then: read the vertex.

Last: check.

Answer
= (x + 3)2 − 4

Your turn

Try this one yourself, then check:

y = x2 + 6x + 1 in vertex form
Show the answer
y = (x + 3)2 − 8

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