Steply

y = tan^-1(4x^2), find dy/dx

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find dy/dx for y = tan⁻¹(4x²).

y = tan⁻¹(4x2)

1 The rule

The rule: the derivative of tan⁻¹ u is 1/(1 + u²).

tan⁻¹ u → 11 + u²

2 The inside

There is something inside: 4x².

Call it u.

u = 4x2

3 The outside

First the outside: the rule on tan⁻¹ u.

dydu = 11 + u²

4 The inside's slope

The inside's slope: the power rule on 4x² gives 8x.

dudx = 8x

5 Multiply

The chain rule: multiply the two, and put 4x² back in place of u.

dydx = 11 + (4x2)2 × 8x

Careful!

Do not stop at the outside.

Multiply by the inside's slope, 8x.

Careful: not 11 + (4x2)2 ✗

Square the inside: (4x²)² is 16x⁴.

(4x2)2 = 16x4

Tidy up: dy/dx = 8x/(1 + 16x⁴).

= 8x1 + 16x4

6 Check

Let's check: the derivative is the slope.

At x = 1, our answer gives 0.4706, with a calculator in radians.

dy/dx at x = 1: 0.4706

Now the slope between two very close points: x = 1 and x = 1.001.

A calculator gives about 0.47.

Very close to 0.4706.

Right!

y(1.001) − y(1)0.001 ≈ 0.47

Let's look back.

First: the rule.

Then: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 8x1 + 16x4

Your turn

Try this one yourself, then check:

f(x) = tan⁻¹(2x2)
Show the answer
f′(x) = 4x1 + 4x4

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