Steply

z = xy, x = 2t, y = t^2, find dz/dt

Step by step, with the reason for every step · Chain rule with several variables · Calculus 3

Step by step

The question

Question: find dz/dt when z = xy, x = 2t and y = t².

z = xy, x = 2t, y = t²

1 Draw the tree

Draw a tree.

z depends on x and y.

Each of them depends on t.

Each branch has its own slope.

To go from z down to t, there are two paths.

Multiply along each path, then add the paths.

2 The pieces

Term by term.

In xy, y is fixed and waits in front.

x gives 1.

So y.

So ∂z/∂x = y.

∂z∂x = y

Term by term.

In xy, x is fixed and waits in front.

y gives 1.

So x.

So ∂z/∂y = x.

∂z∂y = x

x = 2t, so dx/dt = 2.

dxdt = 2

y = t², so dy/dt = 2t.

dydt = 2t

3 Use the chain rule

The chain rule: the x path plus the y path.

dzdt = ∂z∂x × dxdt + ∂z∂y × dydt

Put the four pieces in.

dzdt = (y) × (2) + (x) × (2t)

Careful!

Many people use only one path.

z changes through x and through y, so both paths count.

Careful: two paths: add them

4 Write it in t

The answer should be in t only.

So put x = 2t and y = t² in.

x = 2t, y = t²

Each x becomes 2t and each y becomes t².

dzdt = (t2) × (2) + (2t) × (2t)

Multiply each part out: numbers with numbers, and add the powers of t.

dzdt = 2t2 + 4t2

Add the like terms: dz/dt = 6t².

dzdt = 6t2

5 Check

Let's check another way.

Put x and y in first: z = 2t³.

z = 2t³

Its derivative is 6t².

The same answer.

Right!

dzdt = 6t²

Let's look back.

First: draw the tree.

Then: the pieces.

Then: use the chain rule.

Then: write it in t.

Last: check.

Answer
dzdt = 6t2

Your turn

Try this one yourself, then check:

Find z = 4xy, x = t, y = t²
Show the answer
dzdt = 12t²

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