Steply

a_1 = -6, a_n = a_(n-1) + 5, write the explicit rule

Step by step, with the reason for every step · Recursive sequences · Algebra 2

Step by step

The question

Question: a₁ = −6 and aₙ = aₙ₋₁ + 5.

Write the explicit rule: aₙ with n in it.

a1 = −6, an = an−1 + 5

aₙ₋₁ means the term just before aₙ.

A rule that makes each term from the term before is called recursive.

an−1 = the term before an

1 Read the rule

The first terms: −6, −1, 4.

= −6, −1, 4, ...

We add the same number every time.

So it is arithmetic, with d = 5.

+ 5 every time: arithmetic, d = 5

2 Write the explicit rule

The rule from the sequences lesson: the first term, plus (n − 1) times the difference.

an = a1 + (n − 1) × d

Careful!

Not 5n plus the start.

Term 1 adds no jumps yet, so we add d only n − 1 times.

Careful: not an = 5n + −6 ✗

Put in a₁ = −6 and d = 5.

an = −6 + (n − 1) × 5

The bracket is times 5.

n times 5 is 5n.

−1 times 5 is −5.

an = −6 + 5n − 5

Plain numbers go together: −6 − 5 is −11.

So aₙ = 5n − 11.

an = 5n − 11

3 Check

Let's check with term 3.

The recursive rule gave 4.

recursive: a3 = 4

The explicit rule with n = 3 gives 4 too.

It works!

explicit: a3 = 5(3) − 11 = 4

Let's look back.

First: read the rule.

Then: write the explicit rule.

Last: check.

Answer
an = 5n − 11

Your turn

Try this one yourself, then check:

a1 = −5, an = an−1 + 6, explicit rule?
Show the answer
an = 6n − 11

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