Steply

a_n = 5 × (-2)^(n-1), write the recursive rule

Step by step, with the reason for every step · Recursive sequences · Algebra 2

Step by step

The question

Question: aₙ = 5 × (−2)ⁿ ⁻ ¹.

Write the recursive rule: each term from the term before.

an = 5 × (−2)n − 1

Careful!

A recursive rule needs two parts: the start a₁, and how to get the next term.

Without a₁ we cannot begin.

Careful: a recursive rule needs its start, a₁

1 Find the first terms

We put n = 1, 2 and 3 into the rule.

n = 1 gives 5.

a1 = 5 × (−2)0 = 5

n = 2 gives −10.

a2 = 5 × (−2)1 = −10

n = 3 gives 20.

a3 = 5 × (−2)2 = 20

2 Find the jump

The list: 5, −10, 20.

= 5, −10, 20, ...

So each term is the term before, times −2.

−10 ÷ 5 = −2

3 Write the recursive rule

The start is a₁ = 5.

The rule: aₙ = −2aₙ₋₁.

= a1 = 5, an = −2an−1

4 Check

Let's check with term 4.

The explicit rule gives −40.

explicit: a4 = 5 × (−2)3 = −40

The recursive rule: the term before is 20, so −2 × 20 is −40.

The same.

It works!

recursive: a4 = −2 × 20 = −40

Let's look back.

First: find the first terms.

Then: find the jump.

Then: write the recursive rule.

Last: check.

Answer
= a1 = 5, an = −2an−1

Your turn

Try this one yourself, then check:

an = 4 × (−4)n − 1, recursive rule?
Show the answer
a1 = 4, an = −4an−1

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