Steply

a_n = 2 × 3^(n-1), write the recursive rule

Step by step, with the reason for every step · Recursive sequences · Algebra 2

Step by step

The question

Question: aₙ = 2 × 3ⁿ ⁻ ¹.

Write the recursive rule: each term from the term before.

an = 2 × 3n − 1

Careful!

A recursive rule needs two parts: the start a₁, and how to get the next term.

Without a₁ we cannot begin.

Careful: a recursive rule needs its start, a₁

1 Find the first terms

We put n = 1, 2 and 3 into the rule.

n = 1 gives 2.

a1 = 2 × 30 = 2

n = 2 gives 6.

a2 = 2 × 31 = 6

n = 3 gives 18.

a3 = 2 × 32 = 18

2 Find the jump

The list: 2, 6, 18.

= 2, 6, 18, ...

So each term is the term before, times 3.

6 ÷ 2 = 3

3 Write the recursive rule

The start is a₁ = 2.

The rule: aₙ = 3aₙ₋₁.

= a1 = 2, an = 3an−1

4 Check

Let's check with term 4.

The explicit rule gives 54.

explicit: a4 = 2 × 33 = 54

The recursive rule: the term before is 18, so 3 × 18 is 54.

The same.

It works!

recursive: a4 = 3 × 18 = 54

Let's look back.

First: find the first terms.

Then: find the jump.

Then: write the recursive rule.

Last: check.

Answer
= a1 = 2, an = 3an−1

Your turn

Try this one yourself, then check:

an = 2 × 4n − 1, recursive rule?
Show the answer
a1 = 2, an = 4an−1

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