Steply

AD bisects angle A, AB = 10, AC = 15, DC = 9, find BD

Step by step, with the reason for every step · A line parallel to a side · Geometry

Step by step

The question

Question: A D cuts angle A in half, with AB = 10, AC = 15, DC = 9: find BD.

1 Use the bisector rule

A D cuts the angle at A into two equal angles.

It is the angle bisector.

It cuts B C in the same ratio as the two sides next to A: B D to D C is like A B to A C.

2 Write the proportion

So: AB over AC equals BD over DC.

ABAC = BDDC

Careful!

Keep the same order on both sides: the matching parts on top, the matching parts at the bottom.

Careful: not ABAC = DCBD ✗

Put the numbers in.

We call BD x: 10/15 = x/9.

1015 = x9

3 Cross multiply

When two fractions are equal, we can cross multiply.

These two are equal.

10 × 9 = x × 15

Work out the multiplications.

90 = 15x

Let's swap the two sides, so x is on the left.

15x = 90

4 Remove the 15

15x means 15 times x.

We want just x.

To remove times 15, we divide by 15.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

15x15 = 9015

15 divided by 15 is 1.

So just x is left.

90 divided by 15 is 6.

9015 = 6

So x = 6!

x = 6

5 Check

Let's check: put 6 in place of x.

First the left side.

Left: 1015 = 10÷515÷5 = 23

Now the right side.

Right: 69 = 6÷39÷3 = 23

Both sides are 2/3.

So x = 6 is right!

Both sides equal 23

So BD = 6.

Let's look back.

First: use the bisector rule.

Then: write the proportion.

Then: cross multiply.

Then: remove the 15.

Last: check.

Answer
x = 6

Your turn

Try this one yourself, then check:

Find BD.
Show the answer
BD = 2

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