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Area of parallelogram base 9, side 6, height 5

Step by step, with the reason for every step · Parallelogram and trapezoid · Geometry

Step by step

The question

Question: find the area of a parallelogram with base 9 and height 5.

The slanted side is 6.

1 Make a rectangle

A parallelogram has two pairs of parallel sides.

It looks like a rectangle pushed over.

The height goes straight up from the base.

It makes a right angle with the base.

Cut off the triangle at the left end.

Move it to the right end.

It fits exactly.

Now it is a rectangle, 9 long and 5 high.

Nothing was added or lost, so the area is the same.

Careful: the slanted side is 6.

It is not the height.

The height goes straight up.

2 Base times height

So the area is base times height: A = b × h.

A = b × h

Now put the numbers in: b = 9 and h = 5.

A = 9 × 5

9 times 5 is 45.

So the area is 45 square units.

A = 45

3 Check

Let's check another way.

A line from corner to corner cuts it into two triangles.

Each triangle is half of base times height.

Both have base 9 and height 5.

12 × 9 × 5 + 12 × 9 × 5 = 22.5 + 22.5 = 45

We get 45 again.

So the area is right!

Let's look back.

First: make a rectangle.

Then: base times height.

Last: check.

Answer
A = 45

Your turn

Try this one yourself, then check:

Find the area.
Show the answer
A = 26

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