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Calculate 4C2

Step by step, with the reason for every step · Combinations · Probability

Step by step

The question

Question: work out 4 C 2.

4C2 =

1 Write the rule

The rule for combinations: n factorial, over r factorial times n minus r, factorial.

nCr = n!r! × (n − r)!

Here n is 4 and r is 2.

n = 4
r = 2

2 Put the numbers in

We put 4 for n and 2 for r.

4C2 = 4!2! × (4 − 2)!

4 minus 2 is 2.

4C2 = 4!2! × 2!

3 Write out and cancel

We write every factorial out.

4C2 = 4 × 3 × 2 × 1(2 × 1) × (2 × 1)

2 times 1 is on top and at the bottom.

They cancel.

What is left is 4 × 3, over 2 × 1.

4C2 = 4 × 32 × 1

Why divide by 2 factorial?

The top, 4 times 3, counts in order.

One group of 2 can be put in order 2 ways.

So each group is counted 2 times.

one group of 2: 2 × 1 = 2 orders
AB, BA

Careful!

4 times 3 counts each group 2 times.

We must divide by 2.

Careful: not 4 × 3 = 12 ✗

4 Work it out

2 times 1 is 2.

4 on top and 2 at the bottom both divide by 2.

What is left is 2 × 3.

4C2 = 2 × 3

2 times 3 is 6.

2 × 3 = 6

So 4 C 2 is 6.

4C2 = 6

5 Check

Let's check: 6 groups, each in 2 orders, make 12.

6 groups × 2 orders = 12

And 4 times 3, in order, is 12.

The same.

So the answer is right!

4 × 3 = 12 ✓

Let's look back.

First: write the rule.

Then: put the numbers in.

Then: write out and cancel.

Then: work it out.

Last: check.

Answer
4C2 = 6

Your turn

Try this one yourself, then check:

Work out 3C2
Show the answer
3C2 = 3

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