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Calculate C(10, 2)

Step by step, with the reason for every step · Combinations · Probability

Step by step

The question

Question: work out 10 C 2.

10C2 =

1 Write the rule

The rule for combinations: n factorial, over r factorial times n minus r, factorial.

nCr = n!r! × (n − r)!

Here n is 10 and r is 2.

n = 10
r = 2

2 Put the numbers in

We put 10 for n and 2 for r.

10C2 = 10!2! × (10 − 2)!

10 minus 2 is 8.

10C2 = 10!2! × 8!

3 Write out and cancel

We write every factorial out.

10C2 = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1(2 × 1) × (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

8 times 7 times 6 times 5 times 4 times 3 times 2 times 1 is on top and at the bottom.

They cancel.

What is left is 10 × 9, over 2 × 1.

10C2 = 10 × 92 × 1

Why divide by 2 factorial?

The top, 10 times 9, counts in order.

One group of 2 can be put in order 2 ways.

So each group is counted 2 times.

one group of 2: 2 × 1 = 2 orders
AB, BA

Careful!

10 times 9 counts each group 2 times.

We must divide by 2.

Careful: not 10 × 9 = 90 ✗

4 Work it out

2 times 1 is 2.

10 on top and 2 at the bottom both divide by 2.

What is left is 5 × 9.

10C2 = 5 × 9

5 times 9 is 45.

5 × 9 = 45

So 10 C 2 is 45.

10C2 = 45

5 Check

Let's check: 45 groups, each in 2 orders, make 90.

45 groups × 2 orders = 90

And 10 times 9, in order, is 90.

The same.

So the answer is right!

10 × 9 = 90 ✓

Let's look back.

First: write the rule.

Then: put the numbers in.

Then: write out and cancel.

Then: work it out.

Last: check.

Answer
10C2 = 45

Your turn

Try this one yourself, then check:

Work out 8C2
Show the answer
8C2 = 28

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