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Calculate 7C2

Step by step, with the reason for every step · Combinations · Probability

Step by step

The question

Question: work out 7 C 2.

7C2 =

1 Write the rule

The rule for combinations: n factorial, over r factorial times n minus r, factorial.

nCr = n!r! × (n − r)!

Here n is 7 and r is 2.

n = 7
r = 2

2 Put the numbers in

We put 7 for n and 2 for r.

7C2 = 7!2! × (7 − 2)!

7 minus 2 is 5.

7C2 = 7!2! × 5!

3 Write out and cancel

We write every factorial out.

7C2 = 7 × 6 × 5 × 4 × 3 × 2 × 1(2 × 1) × (5 × 4 × 3 × 2 × 1)

5 times 4 times 3 times 2 times 1 is on top and at the bottom.

They cancel.

What is left is 7 × 6, over 2 × 1.

7C2 = 7 × 62 × 1

Why divide by 2 factorial?

The top, 7 times 6, counts in order.

One group of 2 can be put in order 2 ways.

So each group is counted 2 times.

one group of 2: 2 × 1 = 2 orders
AB, BA

Careful!

7 times 6 counts each group 2 times.

We must divide by 2.

Careful: not 7 × 6 = 42 ✗

4 Work it out

2 times 1 is 2.

6 on top and 2 at the bottom both divide by 2.

What is left is 7 × 3.

7C2 = 7 × 3

7 times 3 is 21.

7 × 3 = 21

So 7 C 2 is 21.

7C2 = 21

5 Check

Let's check: 21 groups, each in 2 orders, make 42.

21 groups × 2 orders = 42

And 7 times 6, in order, is 42.

The same.

So the answer is right!

7 × 6 = 42 ✓

Let's look back.

First: write the rule.

Then: put the numbers in.

Then: write out and cancel.

Then: work it out.

Last: check.

Answer
7C2 = 21

Your turn

Try this one yourself, then check:

Work out 5C2
Show the answer
5C2 = 10

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