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Calculate 9C2

Step by step, with the reason for every step · Combinations · Probability

Step by step

The question

Question: work out 9 C 2.

9C2 =

1 Write the rule

The rule for combinations: n factorial, over r factorial times n minus r, factorial.

nCr = n!r! × (n − r)!

Here n is 9 and r is 2.

n = 9
r = 2

2 Put the numbers in

We put 9 for n and 2 for r.

9C2 = 9!2! × (9 − 2)!

9 minus 2 is 7.

9C2 = 9!2! × 7!

3 Write out and cancel

We write every factorial out.

9C2 = 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1(2 × 1) × (7 × 6 × 5 × 4 × 3 × 2 × 1)

7 times 6 times 5 times 4 times 3 times 2 times 1 is on top and at the bottom.

They cancel.

What is left is 9 × 8, over 2 × 1.

9C2 = 9 × 82 × 1

Why divide by 2 factorial?

The top, 9 times 8, counts in order.

One group of 2 can be put in order 2 ways.

So each group is counted 2 times.

one group of 2: 2 × 1 = 2 orders
AB, BA

Careful!

9 times 8 counts each group 2 times.

We must divide by 2.

Careful: not 9 × 8 = 72 ✗

4 Work it out

2 times 1 is 2.

8 on top and 2 at the bottom both divide by 2.

What is left is 9 × 4.

9C2 = 9 × 4

9 times 4 is 36.

9 × 4 = 36

So 9 C 2 is 36.

9C2 = 36

5 Check

Let's check: 36 groups, each in 2 orders, make 72.

36 groups × 2 orders = 72

And 9 times 8, in order, is 72.

The same.

So the answer is right!

9 × 8 = 72 ✓

Let's look back.

First: write the rule.

Then: put the numbers in.

Then: write out and cancel.

Then: work it out.

Last: check.

Answer
9C2 = 36

Your turn

Try this one yourself, then check:

Work out 8C2
Show the answer
8C2 = 28

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