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Cumulative frequency: 0-10: 3, 10-20: 7, 20-30: 18, 30-40: 22…

Step by step, with the reason for every step · Cumulative frequency · Statistics

Step by step

The question

Question: for the groups 0-10: 3, 10-20: 7, 20-30: 18, 30-40: 22, 40-50: 10, find the interquartile range.

0-10: 3, 10-20: 7, 20-30: 18, 30-40: 22, 40-50: 10

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 3, 3 + 7 = 10, 10 + 18 = 28, and so on, up to 60.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 3 at 10, because by 10 all 3 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Quartiles

The lower quartile is a quarter of the way up: 60 divided by 4 is 15.

From 15 on the up scale, across to the line, then down: about 22.8.

So Q 1 is about 22.8.

Q1 = read at 60 ÷ 4 = 15: ≈ 22.8

The upper quartile is three quarters of the way up: 45.

From 45 on the up scale, across to the line, then down: about 37.7.

So Q 3 is about 37.7.

Q3 = read at 3 × 15 = 45: ≈ 37.7

5 Interquartile range

The interquartile range is Q3 minus Q1: about 14.9.

The middle half of the values lies in this range.

IQR ≈ 37.7 − 22.8 = 14.9

6 Check

Let's check: the last running total is 60, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 3 + 7 + 18 + 22 + 10 = 60

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: quartiles.

Then: interquartile range.

Last: check.

Answer
IQR ≈ 37.7 − 22.8 = 14.9

Your turn

Try this one yourself, then check:

For the groups 0-10: 4, 10-20: 8, 20-30: 18, 30-40: 25, 40-50: 9
Show the answer
IQR ≈ 15

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