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Cumulative frequency: 0-2: 6, 2-4: 14, 4-6: 22, 6-8: 10, 8-10: 8…

Step by step, with the reason for every step · Cumulative frequency · Statistics

Step by step

The question

Question: for the groups 0-2: 6, 2-4: 14, 4-6: 22, 6-8: 10, 8-10: 8, find the median.

0-2: 6, 2-4: 14, 4-6: 22, 6-8: 10, 8-10: 8

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 6, 6 + 14 = 20, 20 + 22 = 42, and so on, up to 60.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 6 at 2, because by 2 all 6 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Median

The median is the middle value.

Half of 60 is 30.

From 30 on the up scale, across to the line, then down: about 4.9.

So the median is about 4.9.

median = read at 60 ÷ 2 = 30: ≈ 4.9

5 Check

Let's check: the last running total is 60, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 6 + 14 + 22 + 10 + 8 = 60

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: median.

Last: check.

Answer
median = read at 60 ÷ 2 = 30: ≈ 4.9

Your turn

Try this one yourself, then check:

For the groups 0-2: 8, 2-4: 15, 4-6: 19, 6-8: 11, 8-10: 7
Show the answer
median ≈ 4.7

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