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Cumulative frequency: 0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16…

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Step by step

The question

Question: for the groups 0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16, find the interquartile range.

0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 12, 12 + 28 = 40, 40 + 24 = 64, and so on, up to 80.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 12 at 30, because by 30 all 12 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Quartiles

The lower quartile is a quarter of the way up: 80 divided by 4 is 20.

From 20 on the up scale, across to the line, then down: about 38.6.

So Q 1 is about 38.6.

Q1 = read at 80 ÷ 4 = 20: ≈ 38.6

The upper quartile is three quarters of the way up: 60.

From 60 on the up scale, across to the line, then down: about 85.

So Q 3 is about 85.

Q3 = read at 3 × 20 = 60: ≈ 85

5 Interquartile range

The interquartile range is Q3 minus Q1: about 46.4.

The middle half of the values lies in this range.

IQR ≈ 85 − 38.6 = 46.4

6 Check

Let's check: the last running total is 80, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 12 + 28 + 24 + 16 = 80

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: quartiles.

Then: interquartile range.

Last: check.

Answer
IQR ≈ 85 − 38.6 = 46.4

Your turn

Try this one yourself, then check:

For the groups 0-30: 14, 30-60: 25, 60-90: 26, 90-120: 19
Show the answer
IQR ≈ 49.3

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