Steply

Cumulative frequency: 140-150: 4, 150-160: 12, 160-170: 20, 170-180…

Step by step, with the reason for every step · Cumulative frequency · Statistics

Step by step

The question

Question: for the groups 140-150: 4, 150-160: 12, 160-170: 20, 170-180: 10, 180-190: 2, find the interquartile range.

140-150: 4, 150-160: 12, 160-170: 20, 170-180: 10, 180-190: 2

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 4, 4 + 12 = 16, 16 + 20 = 36, and so on, up to 48.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 140, with 0: nobody is below the first class.

Each total goes at the END of its class: 4 at 150, because by 150 all 4 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Quartiles

The lower quartile is a quarter of the way up: 48 divided by 4 is 12.

From 12 on the up scale, across to the line, then down: about 156.7.

So Q 1 is about 156.7.

Q1 = read at 48 ÷ 4 = 12: ≈ 156.7

The upper quartile is three quarters of the way up: 36.

From 36 on the up scale, across to the line, then down: about 170.

So Q 3 is about 170.

Q3 = read at 3 × 12 = 36: ≈ 170

5 Interquartile range

The interquartile range is Q3 minus Q1: about 13.3.

The middle half of the values lies in this range.

IQR ≈ 170 − 156.7 = 13.3

6 Check

Let's check: the last running total is 48, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 4 + 12 + 20 + 10 + 2 = 48

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: quartiles.

Then: interquartile range.

Last: check.

Answer
IQR ≈ 170 − 156.7 = 13.3

Your turn

Try this one yourself, then check:

For the groups 140-150: 4, 150-160: 11, 160-170: 23, 170-180: 10, 180-190: 4
Show the answer
IQR ≈ 12.8

More from Cumulative frequency

The whole lesson: Cumulative frequency →