Step by step
The question
Question: find the determinant of this matrix.
D = |2, −3; 1, 4|
The determinant is one number we get from a square matrix.
We write the matrix between two straight lines, and call it D.
1 Multiply the diagonals
So D = 2 × 4 − 1 × (−3).
D = 2 × 4 − 1 × (−3)
Careful!
The up product is −3, a negative number.
Taking it away is adding: 8 − (−3) = 8 + 3.
Careful: not 8 − 3 ✗
2 Down minus up
2 times 4 is 8.
1 times (−3) is −3.
D = 8 − (−3)
Taking away a negative is adding: 8 + 3.
8 − (−3) = 8 + 3
8 minus (−3) is 11.
So D = 11.
D = 11
3 Check
Let's check the taking away by adding back: 11 + (−3) = 8, the down product.
So D = 11 is right!
11 + (−3) = 8
Let's look back.
First: multiply the diagonals.
Then: down minus up.
Last: check.
Answer
D = 11