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Diagonal of a box 1 by 1 by 1

Step by step, with the reason for every step · Pythagoras in 3D · Geometry

Step by step

The question

Question: find the diagonal of a box 1 by 1 by 1.

box 1 by 1 by 1

The diagonal goes from a bottom corner to the top corner on the other side, right through the box.

1 Floor diagonal

First the floor.

Its diagonal d makes a right triangle with the sides 1 and 1.

Pythagoras: d squared is 1 squared plus 1 squared.

1 times 1 is 1.

1 times 1 is 1.

Together 2.

d2 = 12 + 12 = 1 + 1 = 2
a² + b² = c²

2 is not a square number.

We do not need d itself: the next step uses d squared.

keep d² = 2

Careful!

We cannot just add the sides.

A diagonal is a short cut: Pythagoras, twice.

Careful: not 1 + 1 + 1 = 3 ✗

2 Diagonal of the box

Now a new right triangle stands up: the floor diagonal d, the height 1, and the diagonal D of the box.

Pythagoras again: D squared is d squared plus 1 squared.

d squared is 2.

1 times 1 is 1.

Together 3.

D2 = d2 + 12 = 2 + 1 = 3

3 is not a square number.

A calculator gives 1.732, and so on.

D = √3 = 1.732…

To the nearest tenth, D is about 1.7.

D ≈ 1.7

3 Check

Let's check: the two steps are the same as l squared plus w squared plus h squared.

1 plus 1 plus 1 is 3, the same D squared.

So the answer is right!

1² + 1² + 1² = 1 + 1 + 1 = 3

Let's look back.

First: floor diagonal.

Then: diagonal of the box.

Last: check.

Answer
D ≈ 1.7

Your turn

Try this one yourself, then check:

box 3 by 5 by 4
Show the answer
D ≈ 7.1

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